An empirical relationship exists between mean, median and mode. For a moderately skewed distribution it is:

If a frequency distribution has a symmetrical frequency curve, the mean, median and mode are equal.
 If a frequency distribution is positively skewed, then mean is greater than median and median is greater than mode.
 If a frequency distribution is negatively skewed, then mean is less than median and median is less than mode.
Since median always lies between mean and mode in a moderately skewed distribution, therefore it is considered as most realistic measure of central tendency.
Problem: For a moderately skewed distribution mode = 50.04, mean = 45, Find median.
Solution:
Problem: If median = 20, and Mean = 22.5 in a moderately skewed distribution then compute approximate value of mode.
Solution:
thanx for providing valuable information
Thanks
its very funny
Hi everyone it’s Sweety studying 10th standard I want a clear derivation of empirical relation between mean,mode, and median
Can anyone suggest a link or the website
Thank you
Sweety
U never described the symbols in the graph, its like they are contradicting with the statements.
thanks! =D
thanks for giveing a hint…
thanks its good to understand in short time.
It will be so much enriched if mean,median,mode of distributions like Binomial,normal and others are added.
Thank you
It doesn’t always work
Can i write it as 3median = mode 1+ 2mean
despite the facts that you have interesting topics i cannot copy to do revision when i am chanced and my email is not accepted thanks
more flesh to be added