# Quartile deviation for Grouped Data

Quartile deviation or semi-interquartile range is the dispersion which shows the degree of spread around the middle of a set of data. Since the difference between third and first quartiles is called interquartile range therefore half of interquartile range is called semi-interquartile range also known as quartile deviation. For both grouped and ungrouped data, quartile deviation can be calculated by using the formula:

### Coefficient of Quartile Deviation:

Coefficient of Quartile Deviation is used to compare the variation in two data. Since quartile deviation is not affected by the extreme values therefore it is widely used in the data containing extreme values. Coefficient of Quartile Deviation can be calculated by using the formula:

The concept of quartile deviation and coefficient of quartile deviation can be explained with the help of simple problems for grouped data.

### For Grouped Data

Problem: Following are the observations showing the age of 50 employees working in a whole sale center. Find the quartile deviation and coefficient of quartile deviation.

Solution:

In case of frequency distribution, quartiles can be calculated by using the formula:

### First Quartile (Q1)

In case of frequency distribution first quartile can be calculated by using the formula given below:

### Third Quartile (Q3)

Like first and second quartile, the third quartile can be calculated by using the formula:

By putting the values into the formulas of quartile deviation and coefficient of quartile deviation we get:

### 43 responses to Quartile deviation for Grouped Data

????? says:

its a good lesson,thanks for this one

mpeli mwasumbi says:

its a good lesson, it helps to understand the topic.thanks much for this

Tindwa John says:

I have enjoyed a lot in this lesson, you helps many who have problems in maths. Thanks alot

John Isaac Piccio says:

Thanks!

charles says:

thanks so much. but i have a little bit of correction
in the computation for the third quartile, should it be 60.4375 not 60.63…
but THANKS SO MUCH. i had a hard time understanding this because the formula of my prof is a bit different from yours but when I look at it, they’re just the same. 😀

Carlos says:

Nice one I like it and it help me a lot

pranja says:

it is very good lesson for solving problem

Daniel says:

Thanks a lot bro! 😀

chipofya elias says:

nice topic keep it up

M.raza shah says:

Its very easy to understand but if the data is give as…
5_10=3
10_15=5
15_20=7 then how will we find commulative frequecy for such data please iam confused in this i need to know its solution. Thanks

irfan shah says:

Dear friend , i learn a lot of things , because it was easy to understand. thank you

Kondo Jared says:

thanks for assisting me

anam says:

Joly Kenny says:

Thanks a lot!!!!!!!!!!!!! you helped me to solve the problem with all the steps…..

Faith E says:

It was of great help. Thanks so much. Please the correct answer for Q3 is 60.4375.

Thanks. This presentation makes the calculations very simple. Even a high school student can follow through. I now have a good insight on quartile deviation for grouped and ungrouped data.

urooj says:

its very nice…now i’ve got it

sana says:

awsome explanation…

justine mauredi(sheema uganda) says:

thanks a lot dear,i will do my assignment easily

danish says:

chesebe john says:

Zuniya says:

Solved my problem……thanks…..:):):)

Utsab Barman says:

Thanks a lot …

Afghan says:

Thank You so much Mr. Admin
It really helped me alot, keep ur good work up, we appreciate it.

collorizy says:

rex says:

thanks i learned much

dray says:

Brother u av really done a good job,tnks 4 assisting me……luv ya

nice!!! and thank you i’ve done my activities with the help of your examples and formulas…..

francis wambua says:

it has been a friendly lesson…thanks for the lesson

paro says:

huh too long but too easy thnx for given this on net ????

thanks alot…. its really help me….. Good keep it up

Uchenna says:

It made the understanding of quartiles simple, thanks

fm special says:

The last step I.e while calculating the coefficient of quartile deviation, is faulty…How can 60.63-50.016 =110.60…

Kidia says:

Thanks i understand it now

Jazakullah Khairull jazah

wanjau says:

kudos! Deserves a part on ya back. Can see light.

justine says:

thnx so much 4 the help am so grateful

george says:

thanks so very much for the information

Caleb ogola says:

I have really enjoyed the lesson

cliffe morgan says:

thanks for the lesson

cass says:

you can teach better than my teacher. lol.